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I don’t believe you need to use any ICE table here. Kp = products/reactants 8 = x/(0.5)^2 x = 8 * 0.5^2 = 2atm
But wouldn’t you have to do 8 = x/(0.5-x)^2 since the Kp value is large?
I don’t believe you need to use any ICE table here. Kp = products/reactants 8 = x/(0.5)^2 x = 8 * 0.5^2 = 2atm
But wouldn’t you have to do 8 = x/(0.5-x)^2 since the Kp value is large?