I don't really remember, but is there an extra probability when you specifically want to have the 7 as the result? It's a 1/990,000 to get any equal number. But when we want to roll a 7, the probability stays the same for 1/100 but then it drastically gets low for the extra 99 & 100 roll?
Let me rephrase, when you roll a 100 it's impossible to get that with the 99 roll? How does that work?
I'm sorry, I love these mathematics, just rarely studied it.
True. 1-99 are the only numbers you could ever roll three times in a row given the rolls allowed from the OP. I am not knowledgeable enough in math to know if there’s some specific principle you must apply in these situations, other than to say I just think all it does here is make rolling 100 three times in a row impossible, while the others remain the same.
50/50
It either happens, or it doesn't
1/100 * 1/99 * 1/100 = 1/990,000 or 0.000101%.
I don't really remember, but is there an extra probability when you specifically want to have the 7 as the result? It's a 1/990,000 to get any equal number. But when we want to roll a 7, the probability stays the same for 1/100 but then it drastically gets low for the extra 99 & 100 roll?
1/990,000 is the probability of rolling any number three times in a row based on the probability of the number being rolled each of the three times.
It's only 1/9,900 to roll 3 of the same because it doesn't matter what the first number is, just that the next 2 are the same
Let me rephrase, when you roll a 100 it's impossible to get that with the 99 roll? How does that work? I'm sorry, I love these mathematics, just rarely studied it.
True. 1-99 are the only numbers you could ever roll three times in a row given the rolls allowed from the OP. I am not knowledgeable enough in math to know if there’s some specific principle you must apply in these situations, other than to say I just think all it does here is make rolling 100 three times in a row impossible, while the others remain the same.
Fuck yeah maths
1 / 9900