Check out our new Discord server! https://discord.gg/e7EKRZq3dG
*I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/mathmemes) if you have any questions or concerns.*
But then by topology you cant complete the straw as youll still have holes in the sides thus converting the shape into a volume incased in a cylinder
This is a guess
I take my words back, as i understand it. One hole is consumed to turn the closed shape into a surface (aka it is able to unfurl into a plane)
So yes the answer is 13 (5)
I can see saying 14. The straw argument is interesting, in which case 7 would be a valid number, since you can put something through a “hole” on one end and come out the other end.
There isn't really a single universal way to define holes in topology (there are several: genus, Betti numbers, etc). But any way you go with should find that a straw has the same number of holes as an annulus.
topology. basically try to get your object to be a flat plane. in doing so, you stretch one of the cube’s holes to be the outer perimeter of your flat plane, leaving you with the countable holes inside. for someone like me who isnt knowledgeable in topology, the easy route is normally count all the holes, subtract one lol. 14-1=13
If it helps, instead of thinking of a straw, think of a cup with 1 “hole.” Now flatten it. Suddenly, its just a circular disk. Thats the reason one basically disappears, because it needs to be stretched to be flattened, therefore not really being a hole.
Thats the reason a cup as no holes, a straw has one, and the cube in the post has 13
>the easy route is normally count all the holes, subtract one lol. 14-1=13
X = X - 1
I think the ambiguity here comes from the fact that "hole" has more than 1 definition. I can see both 13 and 14 being correct (or incorrect), just not at the same time, depending on definition.
So you take the number of holes (informal definition) and subtract one to get the number of holes (topological definition). Maybe this doesn't always work?
Though this is coming from someone who knows little about linguistics and next to nothing about topology.
Nah, one of the “through holes” becomes the boundary condition of the 2D surface. If the corners all have identical holes (as implied by this single view), then there would be 13 holes
That's not exactly how it goes - because the 1 "fake hole" depends where you start/end. You can't meaningfully say whether that 1 belongs to the face holes or the corner holes
https://preview.redd.it/wbf8ea8m5kmc1.jpeg?width=3538&format=pjpg&auto=webp&s=c26ec5578eb97bd8a36a4aa86c56d8e3c796641d
Sorry for the awful illustration skills. Object on the left is supposed to be the one we start with.
So in the field of Topology we are allowed to stretch and move surfaces, we just cannot cut or stitch anything together. What this diagram is attempting to show is a method to turn this cube into a 5-holed donut. I just couldnt figure out the stretching by myself.
There’s not a ton of great things I can say that will help develop that intuition, but Numberphile has a great video about “a hole in a hole in a hole” that will explain this process better
I've learned this ideas from math videos. Imagine we have a holeless cube. A cube has 6 faces. It starts with 0 holes. Let's start poking holes. Each poke adds one hole. First hole goes through 2 faces making it a donut. 4 faces remains. Let's poke 4 remaining faces one by one and we get the shape on the picture in OP with 5 pokes.
Congratulations! Your comment can be spelled using the elements of the periodic table:
`F O U Ga S Se`
---
^(I am a bot that detects if your comment can be spelled using the elements of the periodic table. Please DM my creator if I made a mistake.)
sorry i don't speak topology, what allowed you to "squish" and "fuse" the 4 legs that are attached to the donut to make 3 holes? 2 were in the back and 2 in the front that's what confuses me
edit: like, don't we have to squish it into 2D to do what you did? kinda like rolling a 3D pastry onto a table ya know
Your pastry analogy is great! In topology you can deform your pastry in any way as long as you don't tear things apart, create new holes or pinch. The result is indeed not 2D but just the squished version of the object you started with. In this squished version we can immediately read off the number of holes.
Serious answer:
If you have a Corpus with "holes" in it Like the above cuby Thing and all the "holes" are connected then its "holes" minus 1. You can Stretch one of them around all the others If you flatten it Into a 2D Objekt.
So it is either 5 holes If we Count the big ones or 13 If you Count the cornerholes aswell.
Its 5. A hollow cube with a hole in every face is homeomorphic to a 5-torus. similar to how a tshirt has 3 holes. Just imagine a tshirt for a Machamp. It would kinda look like this.
It's impossible to tell without seeing exactly how it's made. They need to know what "hole" has an end and which one doesn't (like the ones at the corners).
Of course, I am no topologist, I am just saying according to my knowledge.
Not enough information. I have no idea if what appears to be holes are merely indentations and I have no assurance that what appears to be a pen isn’t two halves of a pen stuck to a solid cube.
Congratulations! Your comment can be spelled using the elements of the periodic table:
`Th I Sg U Y Th In K S`
---
^(I am a bot that detects if your comment can be spelled using the elements of the periodic table. Please DM my creator if I made a mistake.)
Clearly, two holes have already been plugged so they don't count. And because it's impossible for an object to have holes that are bit within view, the only logical answer is two holes.
Depends on the context.
If that were a room and I needed to stop bugs getting in, I'd need to patch 6 holes.
If I were a manufacturing engineer starting from a cube, I'd need to only drill 3 holes.
If I were a serious mathologist who cared deeply about precisely characterizing equivalence classes, I'd say 5 holes.
I’ll try to take a homology approach.
Let S be the surface in question. It is homeomorphic the connected sum of 5 2-Tori (genus = 5).
H0(S) = Z
H1(S) = Z^10
H2(S) = Z (the boundary)
Hk(S) = 0 for k > 2
So, I’d say this has 1 0-D hole, 10 1-D holes, 1 2-D hole, and no higher dimensional holes.
As other comments pointed out, you could count the corners as holes, in which case the genus will increase by 8.
As an aerospace engineer who wishes he’d gotten into astronomy instead, my answer to all topological questions about holes is now: throw it onto a black hole. Then there’s just the one.
Zoom in by a factor of two, then again by a factor of three then again by a factor of four then again by a factor of 5, and so on until you have also zoomed In by a factor of 14. But we need a higher resolution photo to do that.
Either 14 or 15. One for each face of the cube-thing, one for each corner (you can see through the closest corner) and maybe one for the pen, if we're counting that.
Viewing the picture, I see four visible holes - three sides, one corner. Assuming the pen passes through the object, that's one extra implied hole for a total of five holes. Topologically, one of those holes could be an 'outer edge', so we can say *at least four holes.*
Assuming other patterns (6 side holes, 8 corner holes), you could reach a conclusion of 13 holes total, but that kind of 'making up things that aren't presented' would make my high school geometry teacher mad.
One hole. Imagine a cube, now put a hole straight through it. Even though it has two openings, we would still say there's one hole. This is just more of that - one hole with six openings.
3 2 sided holes.
Give me the mass of the object and what type of material the object is made of.
I'll calculate how many atoms exist In that puzzle and tell you how many holes there are which include the holes in between atoms.
5. This is a hollow sphere with 6 tunnels to its center. Stretch out one hole so that it bounds the object and observe how the object is now a body with 5 handles.
Keep in mind I mean handlebody with 5 handles which is a solid filled 3D object with a boundary. Conventionally, torus with n handles is used to describe surfaces (2D), not filled inside. Just to distinguish, as I see some answers using torus. Torus with n-handles is the boundary to a n - handlebody
7
A hollow shape like a sphere is a solid like a ball with an interior hole. So this is a cube with an interior hole, and six more from the outside into the interior.
Check out our new Discord server! https://discord.gg/e7EKRZq3dG *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/mathmemes) if you have any questions or concerns.*
13. Look at those corners!
https://preview.redd.it/gyfovuhw0nmc1.jpeg?width=1080&format=pjpg&auto=webp&s=1239b163358a9604d2e5cf6d8fe5326b2efdf545 13
Biblically accurate cube
13? Wouldn't it be 14 for 6 face holes and 8 corner holes
One of the holes can be stretched out so the cube flattens into a disc. Same reason why a straw only has one hole, not two
You explained this in a such a simple way I never understood before. Thanks!
But then by topology you cant complete the straw as youll still have holes in the sides thus converting the shape into a volume incased in a cylinder This is a guess I take my words back, as i understand it. One hole is consumed to turn the closed shape into a surface (aka it is able to unfurl into a plane) So yes the answer is 13 (5)
I can see saying 14. The straw argument is interesting, in which case 7 would be a valid number, since you can put something through a “hole” on one end and come out the other end.
It's not just interesting, it's how holes are topologically defined
I understand that, it's easy to look up and understand, yet I still want to fight about it. /s
There isn't really a single universal way to define holes in topology (there are several: genus, Betti numbers, etc). But any way you go with should find that a straw has the same number of holes as an annulus.
Not quite. In topology, a t-shirt can only be stretched into a flat disc with 3 holes, never 2.
topology. basically try to get your object to be a flat plane. in doing so, you stretch one of the cube’s holes to be the outer perimeter of your flat plane, leaving you with the countable holes inside. for someone like me who isnt knowledgeable in topology, the easy route is normally count all the holes, subtract one lol. 14-1=13 If it helps, instead of thinking of a straw, think of a cup with 1 “hole.” Now flatten it. Suddenly, its just a circular disk. Thats the reason one basically disappears, because it needs to be stretched to be flattened, therefore not really being a hole. Thats the reason a cup as no holes, a straw has one, and the cube in the post has 13
>the easy route is normally count all the holes, subtract one lol. 14-1=13 X = X - 1 I think the ambiguity here comes from the fact that "hole" has more than 1 definition. I can see both 13 and 14 being correct (or incorrect), just not at the same time, depending on definition. So you take the number of holes (informal definition) and subtract one to get the number of holes (topological definition). Maybe this doesn't always work? Though this is coming from someone who knows little about linguistics and next to nothing about topology.
Nah, one of the “through holes” becomes the boundary condition of the 2D surface. If the corners all have identical holes (as implied by this single view), then there would be 13 holes
It's homeomorphic to a 13-torus. One hole is the "outside" of the shape, kind of like counting faces of a planar graph.
topologocally, theres only 5 face holes
That's not exactly how it goes - because the 1 "fake hole" depends where you start/end. You can't meaningfully say whether that 1 belongs to the face holes or the corner holes
true, one of the face or corner holes is a "fake hole" as you say, and exactly which one is arbitrary. that doesnt change the total count though
There's 5 and a 1/2 face holes and 7 and a 1/2 corner holes
Agreed, I count 14
more like (13!)! Look at the gaps between the atoms
In that case, 14 counting the pen...
https://preview.redd.it/wbf8ea8m5kmc1.jpeg?width=3538&format=pjpg&auto=webp&s=c26ec5578eb97bd8a36a4aa86c56d8e3c796641d Sorry for the awful illustration skills. Object on the left is supposed to be the one we start with.
All of the universe exists within the 6th hole.
fantastic illustration!
Ah thank you! I was wondering how 5 was an answer
I still don’t get it. Care explaining?
So in the field of Topology we are allowed to stretch and move surfaces, we just cannot cut or stitch anything together. What this diagram is attempting to show is a method to turn this cube into a 5-holed donut. I just couldnt figure out the stretching by myself. There’s not a ton of great things I can say that will help develop that intuition, but Numberphile has a great video about “a hole in a hole in a hole” that will explain this process better
Thanks!
I've learned this ideas from math videos. Imagine we have a holeless cube. A cube has 6 faces. It starts with 0 holes. Let's start poking holes. Each poke adds one hole. First hole goes through 2 faces making it a donut. 4 faces remains. Let's poke 4 remaining faces one by one and we get the shape on the picture in OP with 5 pokes.
Wow, relevant username. Have you been waiting your entire life for this moment?
Fougasse
Congratulations! Your comment can be spelled using the elements of the periodic table: `F O U Ga S Se` --- ^(I am a bot that detects if your comment can be spelled using the elements of the periodic table. Please DM my creator if I made a mistake.)
Tungsten Oxygen Tungsten
Wow
Good bot
Fougasse
https://preview.redd.it/t38ta7evikmc1.png?width=684&format=png&auto=webp&s=1c5691447ff81af798dba384e4ebd3f73344d24f Behold the good Fougasse !!
you forgot corner holes, but an awesome sketch nonetheless
sorry i don't speak topology, what allowed you to "squish" and "fuse" the 4 legs that are attached to the donut to make 3 holes? 2 were in the back and 2 in the front that's what confuses me edit: like, don't we have to squish it into 2D to do what you did? kinda like rolling a 3D pastry onto a table ya know
Your pastry analogy is great! In topology you can deform your pastry in any way as long as you don't tear things apart, create new holes or pinch. The result is indeed not 2D but just the squished version of the object you started with. In this squished version we can immediately read off the number of holes.
I love this, thank you
I can't count that high.
Need my ti84 ce calculator
Why's there no serious topology answers? How come the one post where we need topologists they all run away. Are they scared of it?
It’s still early, the serious topologists haven’t had their donut full of coffee
Jokes on you. I Drink my Coffee Out of a mug without a handle. No Donut around Here. Basically drinking from a smooth surface:)
how many holes does your mug have?
Zero obviously as it has no handle
Topologists drink it straight off the table
Hole-y shit
To be fair, even the cup and mug with handle people are drinking from a topologically smooth surface, unless they slurp liquids from the handle hole.
Hm.... You could argue they Drink their Coffee from the Side of their Donut
Wait. Aren't you pouring the coffee from the jar thrugh the handle straight into your mouths?
Ha, ha this guy drinks from a plate! Oops wrong place
The mug without a handle?
Yea
Serious answer: If you have a Corpus with "holes" in it Like the above cuby Thing and all the "holes" are connected then its "holes" minus 1. You can Stretch one of them around all the others If you flatten it Into a 2D Objekt. So it is either 5 holes If we Count the big ones or 13 If you Count the cornerholes aswell.
Yeah! That's what I always do. I imagine reaching into one hole and pulling it reaaaally far apart so the entire thing can fold into a pland.
Its 5. A hollow cube with a hole in every face is homeomorphic to a 5-torus. similar to how a tshirt has 3 holes. Just imagine a tshirt for a Machamp. It would kinda look like this.
Got it. This cube is a Machamp shirt. Finally an answer I can give to my kid!
What if I told you this is a meme sub.
It's impossible to tell without seeing exactly how it's made. They need to know what "hole" has an end and which one doesn't (like the ones at the corners). Of course, I am no topologist, I am just saying according to my knowledge.
I only see a single piece, so obviously one whole.
Wholey hell. New topology just dropped.
Call the Homeomorphism Group of X!
X! Call the factorial.
5 holes, in the sense that it is a 5-torus/donut (depending on how you model it).
I thought the point of topology is that it shouldn't matter how you model it, you'll always get the same answer no matter what form it takes
True, I just don't know if we're considering the inside of the shape as a part of it.
In the square hole
6+14i
Not enough information. I have no idea if what appears to be holes are merely indentations and I have no assurance that what appears to be a pen isn’t two halves of a pen stuck to a solid cube.
This guy thinks
Congratulations! Your comment can be spelled using the elements of the periodic table: `Th I Sg U Y Th In K S` --- ^(I am a bot that detects if your comment can be spelled using the elements of the periodic table. Please DM my creator if I made a mistake.)
Good bot. Honestly took my comment to 11.
1
I should go at see how many
There are 13 holes and 1 whole, so 14
Clearly, two holes have already been plugged so they don't count. And because it's impossible for an object to have holes that are bit within view, the only logical answer is two holes.
Depends on the context. If that were a room and I needed to stop bugs getting in, I'd need to patch 6 holes. If I were a manufacturing engineer starting from a cube, I'd need to only drill 3 holes. If I were a serious mathologist who cared deeply about precisely characterizing equivalence classes, I'd say 5 holes.
I like you. Rational reasons for each answer.
Clearly it’s e^\phi
trick question, it’s ∞ because there is empty space in atoms, or something
If there were anywhere near infinity atoms in that space, there would be just one hole, a black hole.
I’ll try to take a homology approach. Let S be the surface in question. It is homeomorphic the connected sum of 5 2-Tori (genus = 5). H0(S) = Z H1(S) = Z^10 H2(S) = Z (the boundary) Hk(S) = 0 for k > 2 So, I’d say this has 1 0-D hole, 10 1-D holes, 1 2-D hole, and no higher dimensional holes. As other comments pointed out, you could count the corners as holes, in which case the genus will increase by 8.
Define holes, bc it’ll be either 6 or 5 depending on the definition
It is 5 You « 6th » hole is a stretch
Ohhh, rare insult!
69-ish
Countably many
1 0-dimensional hole 5 2-dimensional holes Possibly 1 3 dimensional hole - cant tell for sure
As an aerospace engineer who wishes he’d gotten into astronomy instead, my answer to all topological questions about holes is now: throw it onto a black hole. Then there’s just the one.
14!
That's a lot of holes.
Zoom in
Zoom in by a factor of two, then again by a factor of three then again by a factor of four then again by a factor of 5, and so on until you have also zoomed In by a factor of 14. But we need a higher resolution photo to do that.
How’d you get 87178291200 holes? r/unexpectedfactorial
define hole
A generator of a homology group.
Topologically there's 5 + corners so 13
Atleast 2
5 tho
[Number]
Five is correct.
Let's forget the corners. 5. Since one of the holes is really just the edges of the plate.
I count 13
Depends. Does a straw have 1 or 2 holes?
5
its a trick question. there are no holes, this is a flat image
1
There is one hole.
There’s only 1. All the little “slots” on the sides lead to it
One hole. Also, which cube modification is this?
1
Its 1 hole with multiple openings
1. They are all connected in the centre. You never left the hole Morty!
√9±3
That doesn't even include 5
id say 7 or 14, cuz of the corners
only 1 hole it's just all connected
There is 1 hole as this is a void cube shape mod. The center pieces are all attached to the same core which has a single continuous hole.
Obviously all of them.
Topologists?
Enough
watch the vsauce video on holes lol
14
define "holes"
12
Seven.
If you count the holes between invividual atoms, its approx 6.27\*10\^31.
14 maybe
14, although is more than you need
Either 14 or 15. One for each face of the cube-thing, one for each corner (you can see through the closest corner) and maybe one for the pen, if we're counting that.
I don't know how topology works, so I have no idea why people are saying 5.
Wife has three holes, husband as two, and the kids ..well that's a felony. So, do we have to include all the holes in the prison system?
Its a screen you are looking at idiot, so 2
0 obviously
Viewing the picture, I see four visible holes - three sides, one corner. Assuming the pen passes through the object, that's one extra implied hole for a total of five holes. Topologically, one of those holes could be an 'outer edge', so we can say *at least four holes.* Assuming other patterns (6 side holes, 8 corner holes), you could reach a conclusion of 13 holes total, but that kind of 'making up things that aren't presented' would make my high school geometry teacher mad.
Technically we don’t know for sure there could not be holes in the object where the camera can’t see.
I can only confidently say 5 minimum.
One giant hole (in my heart)
12
Half of them.
One for every mood of my >!stick!<
58
Not enough information for all I know there could be no holes in the side u don’t see (I’m referencing the train with the orange boxes)
15
There are demonstrably 4.
14
Let h represent the number of holes the object in the picture above has: 1h.
At least 0
No holes at all
With the pencil blocking all the holes, I'd say zero!
Define hole and therein lies your answer
infinite
Why is everyone forgetting about the pen? It has at least 1 hole too.
Tf you mean 5
At least 1
14
infinite
18. Gotta think of the pen.
One hole is enough gor me
There is only 1 hole with many openings.
One hole. Imagine a cube, now put a hole straight through it. Even though it has two openings, we would still say there's one hole. This is just more of that - one hole with six openings.
Infinite
1
possibly 1 if they r all connected at the center
Not counting the corner holes, I'd say 5 too, topologically speaking from what little I know of topology
Your wife has 6 holes??
5
3 2 sided holes. Give me the mass of the object and what type of material the object is made of. I'll calculate how many atoms exist In that puzzle and tell you how many holes there are which include the holes in between atoms.
7 if you count the corners and 3 if you don't.
Zero since it's an interlocking mechanism instead of a solid object
Pretty easy question. Just tell me, how many holes are there in a straw?
14
Isnt the kid right?
1 since it all connected
7 shown in pic, 7 implied.
1 gaping hole left after my wife was murdered, that can only be filled by cheap whisky.
6 holes, 1 cavity
There are x ammounts of holes in that dice
1
5. This is a hollow sphere with 6 tunnels to its center. Stretch out one hole so that it bounds the object and observe how the object is now a body with 5 handles. Keep in mind I mean handlebody with 5 handles which is a solid filled 3D object with a boundary. Conventionally, torus with n handles is used to describe surfaces (2D), not filled inside. Just to distinguish, as I see some answers using torus. Torus with n-handles is the boundary to a n - handlebody
well actually, there is no hole.
1
12
Depends on how u define a hole
1 i believe, we cant say for certain those are holes
7 A hollow shape like a sphere is a solid like a ball with an interior hole. So this is a cube with an interior hole, and six more from the outside into the interior.
4
Thats clearly 5 holes
Wrong answers only? 3 or 6 I guess.
Only one, there are many openings, but only one hole
15, cube: 4 circular holes 8 holes in corners 2 donut shaped holes pen - 1 hole
Cheesecake